This is a puzzle for the number buffs that I found on http://www.mindcipher.com
The year 1978 is such that the sum of the first two digits and the latter two digits is equal to the middle two digits, i.e. 19 + 78 = 97. What is the next year (after 1978) for which this is true? (please do not write computer programs to solve)
Please send your answers either directly on the blog site as comments, or to me at alokgoyal_2001@yahoo.com. If you like the puzzle, please share it with others. If you have interesting puzzles to share, please send them to me at my e-mail given above.
Happy year hunting!
Alok Goyal's Puzzles Page 
next 2307, 2417, 2527…
previous 1868, 1758, 1648..
2417, 2527, 2637 and so on
Considering abcd be the year we get- ab + cd = bc where a,b,c and d are digits.
Two scenarios b + d = c OR b + d = 1c
It can’t be 2c since sum of two single digits cannot exceed 18.
If b+d=c, then a+c=b solving both a+d=0, no valid solutions.
Therefore, we move to next scenario i.e, b+d=1c and a+c+1=b , solving we get a+d=9. Henceforth, substituting value of a=2,3.. and so we can come to our solution.
2108
Divya, this answer does not work. 21 + 08 = 29….but the middle two digits are 10
2307 ?
2307
2307…