Solution to Puzzle #30: Red, White and Blue Weights

This was a relatively difficult puzzle for many children, and I did not get too many responses. The only correct answer amongst the younger lot came from Smiti Mittal – congrats Smiti! I also got a correct answer from Ruchir, and a couple of other people threatened me with a correct answer, but did could not send it J

Here is the correct answer (Sorry no video this time, traveling currently without an iPad):

First balance a red and white ball against a blue and a white ball. If the scales balance, you know that there is a heavy and a light ball on each side. One can then weight the two whites against each other to figure out which is the heavier and lighter one. This in turn will help you determine the lighter and heavier ones for red and blue balls as well by keeping track of the ones you used in the first weighing.

If the two sides do not match in the first weighing, one should be able to quickly realize that the heavier white lies on the side of the heavier side of the balance. For the sake of simplicity, let’s assume that the red lies on the lighter side of the scale and therefore blue lies on the heavier side of scale. For the next weighing, put the original red on one side against the blue that was not used in the first weighing.

If they match, then the original red and the blue used in the second weighing are both light.

If they do not, then one can anyway figure out the lighter and the heavier ones amongst the reds and blues.

Hope you enjoyed the puzzle!

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Puzzle #30: Red, White and Blue Weights

Back to weights – Found this very nice puzzle in Mathematical Circus, by Martin Gardner (Chapter 11, Problem #6). This one was originally created by Paul Curry, who was also an amateur magician.

You have six weights. One pair is red, one pair white and one pair blue. In each pair one weight is a little bit heavier than the other but otherwise appears to be exactly like its mate. The three heavier weights (one of each color) all weigh the same. This is also true of the three lighter weights.

In two separate weighings on a balance scale, how can you identify which is the heavier weight of each pair?

As always, please send the answers to alokgoyal_2001@yahoo.com and if you like the puzzle, please feel free to share with others, specially children.

Happy weighing!

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Solution to Puzzle #29: Scrambled Box Tops

This was a relatively simple puzzle, and as such I got a lot of answers, many of them within minutes of my posting the puzzle. This one was originally solved by Anisha, my 9 year old, on her birthday. I got correct answers from many first timers including Sid Pareek, Kamal Karmakar, Phillip Gerbert and like many times before, from Tishyaa. Well done!

The boxes can be correctly identified by drawing just one marble from the box labelled BW. For the full answer, please go to:

Hope you enjoyed the puzzle!

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Puzzle #29: Scrambled Box Tops

This is very cute puzzle, more like a quick teaser that can be a nice dining table puzzle. I was initially asked this puzzle by a friend of my daughter on her 9th birthday. I rediscovered the problem recently in one of the Martin Gardner books (mathematical puzzles and diversions, Chapter #3, Puzzle #5).

Here it goes:

Imagine that you have three boxes. One containing two black marbles, one containing two white marbles, and the third, one black marble and one white marble. The boxes were labeled for their contents—BB, BW, WW—but someone switched the labels so that every box is now incorrectly labeled. You are allowed to take one marble at a time out of any box, without looking inside, and by this process of sampling you are to determine the contents of all three boxes. What is the smallest number of drawings needed to do this?

 As always, please send your answers to alokgoyal_2001@yahoo.com

Happy boxing!

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Solution to Puzzle #28: Cake Cutting

I got a relatively muted response to this puzzle, but some very interesting answers among them. Specifically, I want to congratulate Mayuri+Mehul, as well as Tishyaa for very innovative answers. Jyotsana Dube also sent a correct answer, but not universally applicable to all cuts of the smaller rectangle.

The original intent of the question was a little different than the answers I received. I have recorded the answer on the following link – would strongly encourage parents to show the video to children, as it teaches the kids an important property of a rectangle.

Hope you enjoyed the puzzle!

 

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Puzzle #28: Cake Cutting

This is a puzzle that I have seen in many different sources, a nice geometry puzzle!

Mary baked a rectangular cake. Merlin secretly carved out a small rectangular piece, ate it and vanished! The remaining cake has to be split evenly between Mary’s two kids. How could this be done with only one cut through the cake?

I would strongly encourage parents to actually draw this out for the children with the rectangles of different sizes and placed at awkward angles.

As always, please send your answers to alokgoyal_2001@yahoo.com

Happy solving!

 

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Solution to Puzzle #27: The 3 Matchstick Heaps

First of all, apologies for the delayed response to the puzzle, I was traveling outside the country on the past weekend.

Thanks to everyone who tried this puzzle – I received one of the best responses to date from this puzzle. The first ones to solve were Abhishek Pal, Ruchir Godura, Christina Beamer, Rohit Gupta (along with Mehul and Mayuri) and Tushar Kamat.

As always, the answer is in the following video link:

Hope you enjoyed this one!

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Puzzle #27: The 3 Matchsticks Heaps

This puzzle is a nice and again a relatively easy one, and the beauty is that children and adults should both enjoy this one. I found this in a puzzle book I bought way back in 1985 – Mathematics can be fun, by Ya. Perelman. There are some other wonderful books by the same author.

When I read the puzzle today morning, I read it wrong, and ended up solving a different puzzle. It so turns out that the original version and the version with my wrong interpretation were both very interesting. So sending both the versions to all of you:

1. A man emptied a box of matches on the table and divided them into three heaps.

“You are not going to start a bonfire, are you?”, someone quipped.

“No, they are for my brain-teaser. Here you are – three uneven heaps. There are altogether 48 matches. I won’t tell how many there are in each heap. If I take as many matches from the first heap as there are in the second and add them to the second, and then take as many from the second as there are in the third and add them to the third, and finally, take as many from the third as there are in the first and add then to the first – well, if I do this, the heaps will all have the same number of matches. How many were there originally in each heap?”

 

2. Another version of the same question – you take the same steps as above, but find that the three heaps have exactly the same number of matches as what you started with initially.

Enjoy the bonfire!

 

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Solution to Puzzle #26: Get to the number 14

This was a relatively simple puzzle and I got many answers immediately as if this were a buzzer round question. Even my 9 year old, gave me multiple answers in succession, in a bid to get to number 14 in the shortest number of steps. The first one to send me the correct answer was Karan Yadav from Canada, and the first one in the younger generation was Ashwin Godura, followed by Anisha Goyal and Tishyaa Chaudhry. Many other children sent me answers to this one, and congratulations to all of them!

This one does not require a video – here are a few different ways to get to the answer in 8 moves:

458 –> 45 –> 90 –> 9 –> 18 –> 36 –> 72 –> 7 –> 14

458 –> 916 –> 91 –>182 –> 364 –> 728 –> 1456 –> 145 –> 14

Hope you enjoyed this one!

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Puzzle #26: Get to the number 14

This is a relatively simple arithmetic puzzle, that I found interesting to do with my 9 year old. I picked this up from Mathematical Circles. Here is the puzzle:

You begin with the number 458. You are only allowed two operations, each of which can be repeated any number of times:

– You can multiply the number by 2

– Remove the last digit, i.e. the one in the unit’s place (e.g. 8 in the number 458)

Your task is to get to the number 14, beginning with 458. Do this in the minimum number of steps.

Happy crunching, and as always, e-mail your answers directly to me at alokgoyal_2001@yahoo.com

 

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