While browsing through mind cipher.com, I came across this wonderful puzzle…a good puzzle for those who love to play with numbers.
It’s said that a number N with 4 digits is a double-square number when it equals the sum of the squares of two numbers: one formed by the first two digits of N, in the order they appear in N and the other formed by the two last digits of N in the order they appear in N.
For example, 1233 is a double-square number since 1233 = 12^2 + 33^2. Find another double-square number.
Please send your answers either directly on the blog site as comments, or to me at firstname.lastname@example.org. If you like the puzzle, please share it with others. If you have interesting puzzles to share, please send them to me at my e-mail given above.
Happy number crunching!
Very nice answer – if 12 works then 100-12 has to work!
For N with 6 digits : 990100 = 990^2+100^2
For N with 8 digits : 94122353 = 9412^2+2353^2