Solution to Puzzle #188: Jars and Paints

Apologies for late posting of the solution to this puzzle, but better late than never!

This puzzle was similar to one of the first puzzles I posted (Milkman and the Three Jars – https://alokgoyal1971.com/2013/02/03/puzzle-2-milkman-and-the-three-jars/). I received correct answers from Suman Saraf (as always!), Tanmay Ratnaparkhe and Sarthak Mitra. Well done all.

I am taking the liberty of copying the entire solution from Tanmay.

Take 3 JARs – 1 , 2 , 3. I have taken liquids A, B ,C and kept the qty as 20 each for easy calculation. The capacity of the Jars is obviously 30. In multiple rounds, the liquids are poured into different jars.

JAR 1 JAR 2 JAR 3 Comments
20A 20B 20C
Round 1 20A + 10B 0 20C + 10 B Pour B equally into JAR 1 and JAR 3
Round 2 10A + 5B 10 A+ 10 B + 10C 10 C + 5 B Pour Half contents of JAR 1 and JAR 3 into JAR 2
Round 3 10 A + 10 B + 10 C 10 A+ 10 B + 10C 0 Pour all contents of JAR 3 into JAR 1
Round 4 20/3 A + 20/3 B + 20/3 C 20/3 A + 20/3 B + 20/3 C 20/3 A + 20/3 B + 20/3 C Divide equally between all 3 JARs
Hope you all enjoyed the puzzle!
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